(-3x^2+2)(x-1)=0

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Solution for (-3x^2+2)(x-1)=0 equation: 


Simplifying
(-3x2 + 2)(x + -1) = 0

Reorder the terms:
(2 + -3x2)(x + -1) = 0

Reorder the terms:
(2 + -3x2)(-1 + x) = 0

Multiply (2 + -3x2) * (-1 + x)
(2(-1 + x) + -3x2 * (-1 + x)) = 0
((-1 * 2 + x * 2) + -3x2 * (-1 + x)) = 0
((-2 + 2x) + -3x2 * (-1 + x)) = 0
(-2 + 2x + (-1 * -3x2 + x * -3x2)) = 0
(-2 + 2x + (3x2 + -3x3)) = 0
(-2 + 2x + 3x2 + -3x3) = 0

Solving
-2 + 2x + 3x2 + -3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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